c++ - differences between new char[n] and new (char[n]) -


is there difference between new char[n] , new (char[n])?

i have second case in generated code, g++ (4.8.0) gives me

iso c++ not support variable-length array types [-wvla] 

this makes me think if these 2 same or not.

  1. new char[n] means "allocate n objects of type char.
  2. does new (char[n]) mean "allocate 1 object of type array of n chars"?
  3. deleting first clear.
  4. should delete second delete or delete[]?
  5. are there other differences should aware of?
  6. may safely remove parentheses , turn second case first, when other parts of software expect second?

the code generated third party software (and used other parts of software), cannot "use vector instead".

this minimal example:

int main (void) {     int n(10);     int *arr = new (int[n]); // removing parentheses fixes warning     *arr = 0; // no "unused variable" warning     return 0; } 

the basic issue here c++ not allow array bound [n] used in type unless n constant expression. g++ , other compilers allow anyway, it's impossible consistent behavior when start mixing variable-length-arrays , templates.

the apparent exception int* p = new int[n]; works because here [n] syntactically part of new expression, not part of type provided new, , new "know how" create arrays length determined @ runtime.

// can "constexpr" in c++11: const int c = 12;  int main() {     int* p1 = new int[c];     int* p2 = new (int[c]);     typedef int arrtype[c];     int* p3 = new arrtype;      int n = 10;     int* p4 = new int[n];     // int* p5 = new (int[n]);  // illegal!     // typedef int arrtype2[n]; // illegal!     // int* p6 = new arrtype2;      delete[] p1;     delete[] p2;     delete[] p3;     delete[] p4; } 

semantically, though, after final [c] used convert type array type, new expression cares whether it's dealing array or not. requirements type of expression, whether use new[] , delete[], , on things "when allocated type array", not "when array new syntax used". in example above, initializations of p1, p2, , p3 equivalent, , in cases delete[] correct deallocation form.

the initialization of p4 valid, code p5 , p6 not correct c++. g++ allow them anyway when not using -pedantic, , analogy i'd expect initializations p4, p5, , p6 equivalent. @mm's disassembly supports conclusion.

so yes, should safe improvement remove "extra" parentheses sort of expression. , correct deletion delete[] type.


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