Conditional loop in python -

list=['a','a','x','c','e','e','f','f','f']  i=0 count = 0  while count < len(list)-2:     if list[i] == list[i+1]:         if list [i+1] != list [i+2]:             print list[i]             i+=1             count +=1         else:print "no"     else:            +=1         count += 1 

i'm getting:

    else:print "no"    ^  indentationerror: unexpected indent 

i'm trying print elts match following element, not element following that. i'm new python, , i'm not sure why isn't working.

here fixed-up code (added count += 1 after else-clause make sure terminates):

list=['a','a','x','c','e','e','f','f','f']  i=0 count = 0  while count < len(list)-2:     if list[i] == list[i+1]:         if list [i+1] != list [i+2]:             print list[i]             i+=1             count +=1         else:             print "no"             count += 1     else:            +=1         count += 1 

a more advanced solution using itertools more compact , easier right:

from itertools import groupby  data = ['a','a','x','c','e','e','f','f','f'] k, g in groupby(data):     if len(list(g)) > 1:         print k