How to pass a parameter in a lambda function in python? -


i want set colors of object, , don't want create 10 functions every color. so, want declare colors , create 10 buttons , 1 function. error message is:

<lambda>() missing 1 required positional argument: 'green' 

the code:

from tkinter import *  green=["#5bd575","#55c76d"] #different colors should follow here  root=tk() btn=button(text="trigger lambda", command=lambda green: printfunction(green)) btn.pack()  def printfunction(colorset):     print(colorset) 

it not need lambda function, question just, how can call printfunction argument clicking button?

the command callable doesn't take any arguments. if want pass green list printfunction, omit argument, lambda doesn't need it:

btn=button(text="trigger lambda", command=lambda: printfunction(green)) 

now green inside lambda refers global.

if wanted call printfunction pre-defined argument, use functools.partial() function; pass function called plus arguments need passed in, , when it's return value called, it'll that; call function arguments specified:

from functools import partial  btn=button(text="trigger lambda", command=partial(printfunction, green)) 

Comments

Popular posts from this blog

SPSS keyboard combination alters encoding -

Add new record to the table by click on the button in Microsoft Access -

CSS3 Transition to highlight new elements created in JQuery -