format - How to center align columns of different lengths using numpy.savetxt in Python? -
i have several lists contain both strings , floats elements.
import numpy num column_1 = ['kic 7742534', 'variable star of rr lyr type' , 'v* v368 lyr', 'kic 7742534', '4.0', '0.4564816'] column_2 = ['kic 76', 'variable star' , 'v* v33 lyr', 'kic 76', '5.0', '0.45'] dat = num.column_stack((column_1, column_2)) num.savetxt('savetxt.txt', dat, delimiter=' ', fmt='{:^10}'.format('%s')) the output when running file following:
kic 7742534 , kic 76 variable star of rr lyr type , variable star v* v368 lyr , v* v33 lyr kic 7742534 , kic 76 4.0 , 5.0 0.4564816 , 0.45 the ideal output (including aligned header)
#element1 element2 kic 7742534 , kic 76 variable star of rr lyr type , variable star v* v368 lyr , v* v33 lyr kic 7742534 , kic 76 4.0 , 5.0 0.4564816 , 0.45 how output (with aligned header), if strings don't have max width defined. have tried modifying format of strings (fmt), no luck far.
-thanks!
you need calculate maximum string length of of longest row of output (or input depending on how @ it), method similar
max_len = max(max(map(len,l)) l in zip(column_1,column_2)) will achieve. after need change fmt parameters dynamically based on value of max_len can so:
fmt=('{:^%d}' % max_len).format('%s')
the following non-numpy example shows expected output:
with open('ofile.txt','w+') f: max_len = max(max(map(len,l)) l in zip(column_1,column_2)) line in zip(column_1,column_2): f.write(','.join(('{:<%s}' % (max_len)).format(e) e in line)+'\n') produces text file ofile.txt containing:
kic 7742534 ,kic 76 variable star of rr lyr type,variable star v* v368 lyr ,v* v33 lyr kic 7742534 ,kic 76 4.0 ,5.0 0.4564816 ,0.45
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