string substitution - Replace a substring in Lua with a pattern -


i have string 

     str = '["username"] = "user";      ["deepscan"] = "true";      ["token"] = true;      ["password"] = "krghfkghkfghf";      ["uploadmethod"] = "json";      ["serviceisrunning"] = {};      ["host"] = "sample.com";      ["instance_id"] = 405454058;'

i pattern match ["password"] = , have replace string in between ";' '"krghfkghkfghf" in instance.

local function replacepass(configstr, newpass)     return configstr:gsub("(%[\"password\"%]%s*=%s*)%b\"\"", "%1\"" .. newpass .. "\"") end

that won't work if password contains double quote inside.


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