c++ - Using normal and overloaded operator at the same time -

i have class , overloaded [ operator use in main. problem here is; somewhere in class in function. want use [ operator old style. how can use them both or how can modify overloaded [ parameter ?

here overloading part.

t &operator[](int i) { if (i < 0 || >= arithmeticvector<t>::size())    throw std::string("out of bounds!"); //throw std::out_of_range; else    return data[i]; }; 

and here function want use;

friend arithmeticvector<t> operator /(const arithmeticvector<t>& v1, const arithmeticvector<t>& v2 ) {   /*do quick size check on vectors before proceeding*/ arithmeticvector<t> result(v1.size());    (unsigned int = 0; < result.size(); ++i) {    result[i]=v1[i]/v2[i]; }    return result; }; 

i error error c2678: binary '[' : no operator found takes left-hand operand of type 'const arithmeticvector'

the problem line.

result[i]=v1[i]/v2[i]; 

overloaded operator didn't :/

i can't understand, mean i want use [] operator old style, should overload operator[] const version too:

const t& operator[](int i) const {     // ... } 

v1 , v2 non-modifiable here, can't call non-const methods.