Javascript/jQuery: Get specific elements from form -

i have extense form around 25 inputs (text, radio , checkboxes). want when click button opens jquery dialog, loads form , set fields except 5 of them disabled. seems easy, want "generic" function. mean, have method:

function disableinputs(jqueryelement, exceptions, booleanclean) {     //some stuff } 

i want inputs jqueryelement, ignoring elements ids have exceptions. exceptions object one:

var exceptions = {     0: 'clientid',     1: 'clientname',     2: 'clientfirstsurname',     3: 'clientsecondsurname',     4: 'clientalias' } 

this full code , i've tested, way make work and, if have recieved third parameter (booleanclean), set value='' inputs, instead elements weren't excluded being disabled. boolean works check if want clean inputs when function called:

function disableinputs(jqueryelement, exceptions, booleanclean) {     var inputs = jqueryelement.find('input');     (var = 0; < inputs.length; i++) {         inputs[i].setattribute('disabled', true);         (var attr in exceptions) {             if (inputs[i].getattribute('id') === exceptions[attr]) {                 inputs[i].removeattribute('disabled');             } else {                 if (booleanclean === true) {                     inputs[i].value = null;                 }             }         }     } } 

i know why not working clean "option". want have put or if can set condition when inputs inputs not excluded (preferible second option optimization , not set attribute each input , remove them if excluded. seems easier work).

try

function disableinputs(jqueryelement, exceptions, booleanclean) {     var not = jquery.map(exceptions, function(item, index){         return '#' + item;     }).join(',')     var inputs = jqueryelement.find(':input').not(not).prop('disabled', true);     if(booleanclean){         inputs.val('')     } }