java - Separate String into two parts -

my string looks this: "/namestart blabla1 /nameend blabla2". ps. might /namestartblabla1/nameendbababa2 example.

i need 2 strings:

string1 == blabla1 string2 == blabla2 

i got strings this:

if(mystring.startswith("/namestart")){     pattern p = pattern.compile("/namestart(.*?)/nameend");     matcher m = p.matcher(mystring);     if (m.find()) {       string string1 = m.group(1);       string string2 = mystring.substring(mystring.indexof("/nameend")+8, mystring.length()));     } } 

first question can done better or solution ok?

and second problem blabla1 , blabla2 can anything, can /nameend (probaby wont be) or screw reg expression. theoretical solution that?

i not sure trying maybe try using groups indexes instead of substring. rid of if(mystring.startswith("/namestart")){ can use ^ anchor @ star of regex indicate matching part should placed @ start of string.

string mystring = "/namestart blabla1 /nameend blabla2";  pattern p = pattern.compile("^(/namestart)(.*?)(/nameend)(.*)"); matcher m = p.matcher(mystring); if (m.find()) {     string string1 = m.group(2);     string string2 = m.group(4);     system.out.println(string1 + "|" + string2); } 

output

 blabla1 | blabla2 

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also depending on trying achieve in situation blabla1 or blabla2 /nameend can try changing (.*?) (.+?).