separator - Python 3.3: separation argument (sep) giving an error -


i new programming , i'm starting out python. tried question here didn't find anything.

i'm trying work simple print command i'm getting error reason don't understand. 

last = 'smith' middle = 'paul' first = 'john' print(first.capitalize(), middle.capitalize(), last.capitalize(), sep='\t')

according answer in book, should right, every time try run it, error 'sep': 

print(first.capitalize(), middle.capitalize(), last.capitalize(), sep='\t')                                                                      ^ syntaxerror: invalid syntax

can tell me i'm doing wrong. it's worth i'm using pyscripter.

[edit]

thanks that. found out i'm using python 2.7.3 instead of 3.3. looked manual see how separator works. seems me difference square bracket. manual describes print function : 

print([object, ...][, sep=' '][, end='\n'][, file=sys.stdout])

so changed print command , added square bracket:

print ([first.capitalize(),middle.capitalize(),last.capitalize()] [, sep='\t'])

but unfortunately doesn't work either error highlights square brackets around sep='\t'. when take brackets out, error doesn't go away.

i'm not sure i'm doing wrong, seems should simple.

you aren't using python 3, think are. try:

import sys print(sys.version)

and see comes out. python 2 print ... statement (not print(...) function in python 3) interprets 

print (first.capitalize(), middle.capitalize(), last.capitalize(), sep='\t')

which trying print tuple keyword argument, syntax error on sep


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